Optimal. Leaf size=124 \[ -\frac{5 \left (1089 m^2-957 m+8\right ) (3 x+2)^{m+1} \, _2F_1(1,m+1;m+2;5 (3 x+2))}{2662 (m+1)}+\frac{8 (3 x+2)^{m+1} \, _2F_1\left (1,m+1;m+2;\frac{2}{7} (3 x+2)\right )}{9317 (m+1)}+\frac{5 (29-33 m) (3 x+2)^{m+1}}{242 (5 x+3)}-\frac{5 (3 x+2)^{m+1}}{22 (5 x+3)^2} \]
[Out]
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Rubi [A] time = 0.316209, antiderivative size = 124, normalized size of antiderivative = 1., number of steps used = 5, number of rules used = 4, integrand size = 22, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.182 \[ -\frac{5 \left (1089 m^2-957 m+8\right ) (3 x+2)^{m+1} \, _2F_1(1,m+1;m+2;5 (3 x+2))}{2662 (m+1)}+\frac{8 (3 x+2)^{m+1} \, _2F_1\left (1,m+1;m+2;\frac{2}{7} (3 x+2)\right )}{9317 (m+1)}+\frac{5 (29-33 m) (3 x+2)^{m+1}}{242 (5 x+3)}-\frac{5 (3 x+2)^{m+1}}{22 (5 x+3)^2} \]
Antiderivative was successfully verified.
[In] Int[(2 + 3*x)^m/((1 - 2*x)*(3 + 5*x)^3),x]
[Out]
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Rubi in Sympy [A] time = 43.1896, size = 104, normalized size = 0.84 \[ \frac{\left (- \frac{15 m}{22} + \frac{145}{242}\right ) \left (3 x + 2\right )^{m + 1}}{5 x + 3} - \frac{5 \left (3 x + 2\right )^{m + 1}}{22 \left (5 x + 3\right )^{2}} - \frac{5 \left (3 x + 2\right )^{m + 1} \left (1089 m^{2} - 957 m + 8\right ){{}_{2}F_{1}\left (\begin{matrix} 1, m + 1 \\ m + 2 \end{matrix}\middle |{15 x + 10} \right )}}{2662 \left (m + 1\right )} + \frac{8 \left (3 x + 2\right )^{m + 1}{{}_{2}F_{1}\left (\begin{matrix} 1, m + 1 \\ m + 2 \end{matrix}\middle |{\frac{6 x}{7} + \frac{4}{7}} \right )}}{9317 \left (m + 1\right )} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] rubi_integrate((2+3*x)**m/(1-2*x)/(3+5*x)**3,x)
[Out]
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Mathematica [A] time = 0.699722, size = 220, normalized size = 1.77 \[ \frac{(3 x+2)^m \left (\frac{22 \left (\frac{3}{5}\right )^m \left (\frac{3 x+2}{5 x+3}\right )^{-m} \, _2F_1\left (1-m,-m;2-m;-\frac{1}{15 x+9}\right )}{(m-1) (5 x+3)}+\frac{121 \left (\frac{3}{5}\right )^m \left (\frac{3 x+2}{5 x+3}\right )^{-m} \, _2F_1\left (2-m,-m;3-m;-\frac{1}{15 x+9}\right )}{(m-2) (5 x+3)^2}+\frac{4 \left (\left (\frac{3}{5}\right )^m \left (\frac{3 x+2}{5 x+3}\right )^{-m} \, _2F_1\left (-m,-m;1-m;-\frac{1}{15 x+9}\right )-\left (\frac{6 x+4}{6 x-3}\right )^{-m} \, _2F_1\left (-m,-m;1-m;\frac{7}{3-6 x}\right )\right )}{m}\right )}{1331} \]
Antiderivative was successfully verified.
[In] Integrate[(2 + 3*x)^m/((1 - 2*x)*(3 + 5*x)^3),x]
[Out]
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Maple [F] time = 0.095, size = 0, normalized size = 0. \[ \int{\frac{ \left ( 2+3\,x \right ) ^{m}}{ \left ( 1-2\,x \right ) \left ( 3+5\,x \right ) ^{3}}}\, dx \]
Verification of antiderivative is not currently implemented for this CAS.
[In] int((2+3*x)^m/(1-2*x)/(3+5*x)^3,x)
[Out]
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Maxima [F] time = 0., size = 0, normalized size = 0. \[ -\int \frac{{\left (3 \, x + 2\right )}^{m}}{{\left (5 \, x + 3\right )}^{3}{\left (2 \, x - 1\right )}}\,{d x} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate(-(3*x + 2)^m/((5*x + 3)^3*(2*x - 1)),x, algorithm="maxima")
[Out]
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Fricas [F] time = 0., size = 0, normalized size = 0. \[{\rm integral}\left (-\frac{{\left (3 \, x + 2\right )}^{m}}{250 \, x^{4} + 325 \, x^{3} + 45 \, x^{2} - 81 \, x - 27}, x\right ) \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate(-(3*x + 2)^m/((5*x + 3)^3*(2*x - 1)),x, algorithm="fricas")
[Out]
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Sympy [A] time = 6.59582, size = 1226, normalized size = 9.89 \[ \text{result too large to display} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate((2+3*x)**m/(1-2*x)/(3+5*x)**3,x)
[Out]
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GIAC/XCAS [F] time = 0., size = 0, normalized size = 0. \[ \int -\frac{{\left (3 \, x + 2\right )}^{m}}{{\left (5 \, x + 3\right )}^{3}{\left (2 \, x - 1\right )}}\,{d x} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate(-(3*x + 2)^m/((5*x + 3)^3*(2*x - 1)),x, algorithm="giac")
[Out]